Copper Bar
5
Jan/100
Jan/100
Determine the linear temperature coefficient of expansion for copper?
given that a copper bar of length 2000 mm expands by 15 mm when heated from
20 °C to 450 °C.
I have the answer 2.32 x 10^ -5
Working formula is
L = Lo(1 + A*delta T)
where
L = length of the material at any given temperature
Lo = original length = 2000 mm (given)
A = coefficient of linear expansion
delta T = 450 - 20 = 430 C
Substituting values,
2000 + 15 = 2000(1 + A*430)
1.0075 = 1 + 430A
Solving for "A"
A = 0.0075/430
A = 1.74 x 10^-5
Hope this helps.
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